stmt: remove extra newlines in output
This commit is contained in:
parent
cdfa7df4fa
commit
6b40079884
19
node.go
19
node.go
@ -69,7 +69,7 @@ func convert(n_ node.Node) (string, error) {
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// Emit deferred statements
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// Emit deferred statements
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if len(statements) > 0 {
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if len(statements) > 0 {
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ret += "func init() {\n"
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ret += "func init() {\n"
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ret += "\t" + strings.Join(statements, "\n\t") + "\n"
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ret += "\t" + strings.Join(statements, "\t") // Statements already added their own newline
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ret += "}\n"
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ret += "}\n"
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}
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}
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@ -79,7 +79,8 @@ func convert(n_ node.Node) (string, error) {
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return n.Value, nil
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return n.Value, nil
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case Literal:
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case Literal:
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return n.Value, nil
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// We expect literal statements to act like a *Stmt, i.e. be emitted with a trailing NL
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return n.Value + "\n", nil
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//
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//
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// stmt
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// stmt
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@ -95,7 +96,7 @@ func convert(n_ node.Node) (string, error) {
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return "", parseErr{s, err}
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return "", parseErr{s, err}
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}
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}
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ret += line + "\n"
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ret += line // Statements already added a trailing newline
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}
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}
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return ret + "}\n", nil
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return ret + "}\n", nil
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@ -922,20 +923,18 @@ func convertFunctionCommon(params []node.Node, returnType node.Node, returnsRef
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}
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}
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// Build function prototype
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// Build function prototype
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ret := "(" + strings.Join(funcParams, ", ") + ") (" + funcReturn + ", error) {\n"
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ret := "(" + strings.Join(funcParams, ", ") + ") (" + funcReturn + ", error) "
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// Recurse through body statements
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// Recurse through body statements
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for _, s := range bodyStmts {
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bodyStmt, err := convert(s)
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fullBody, err := convert(stmt.NewStmtList(bodyStmts))
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if err != nil {
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if err != nil {
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return "", parseErr{s, err}
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return "", err
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}
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}
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ret += bodyStmt + "\n"
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ret += fullBody + "\n"
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}
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// Done
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// Done
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// No extra trailing newline in case this is part of a large expression
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// No extra trailing newline in case this is part of a large expression
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ret += "}"
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return ret, nil
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return ret, nil
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}
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}
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