stmt: remove extra newlines in output

node.go

@@ -69,7 +69,7 @@ func convert(n_ node.Node) (string, error) {
 		// Emit deferred statements
 		if len(statements) > 0 {
 			ret += "func init() {\n"
-			ret += "\t" + strings.Join(statements, "\n\t") + "\n"
+			ret += "\t" + strings.Join(statements, "\t") // Statements already added their own newline
 			ret += "}\n"
 		}
 
@@ -79,7 +79,8 @@ func convert(n_ node.Node) (string, error) {
 		return n.Value, nil
 
 	case Literal:
-		return n.Value, nil
+		// We expect literal statements to act like a *Stmt, i.e. be emitted with a trailing NL
+		return n.Value + "\n", nil
 
 	//
 	// stmt
@@ -95,7 +96,7 @@ func convert(n_ node.Node) (string, error) {
 				return "", parseErr{s, err}
 			}
 
-			ret += line + "\n"
+			ret += line // Statements already added a trailing newline
 		}
 		return ret + "}\n", nil
 
@@ -922,20 +923,18 @@ func convertFunctionCommon(params []node.Node, returnType node.Node, returnsRef
 	}
 
 	// Build function prototype
-	ret := "(" + strings.Join(funcParams, ", ") + ") (" + funcReturn + ", error) {\n"
+	ret := "(" + strings.Join(funcParams, ", ") + ") (" + funcReturn + ", error) "
 
 	// Recurse through body statements
-	for _, s := range bodyStmts {
-		bodyStmt, err := convert(s)
-		if err != nil {
-			return "", parseErr{s, err}
-		}
 
-		ret += bodyStmt + "\n"
+	fullBody, err := convert(stmt.NewStmtList(bodyStmts))
+	if err != nil {
+		return "", err
 	}
 
+	ret += fullBody + "\n"
+
 	// Done
 	// No extra trailing newline in case this is part of a large expression
-	ret += "}"
 	return ret, nil
 }